10x/4-x^2/5/2-x

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Solution for 10x/4-x^2/5/2-x equation: 


x in (-oo:+oo)

(10*x)/4-(((x^2)/5)/2)-x = 0

(-1/10)*x^2+(10*x)/4-x = 0

3/2*x-1/10*x^2 = 0

DELTA = (3/2)^2-(-1/10*0*4)

DELTA = 9/4

DELTA > 0

x = ((9/4)^(1/2)-3/2)/(-1/10*2) or x = (-(9/4)^(1/2)-3/2)/(-1/10*2)

x = 0 or x = 15

x in { 0, 15 }

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